By Ken Butti
Sm 4to, 1980, PP.289,
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1 m 2 . c. 0003 m 3 /s. The simulation interval is 0:::; t:::; 60 s. 22 illustrates a counterflow heat exchanger. A hot liquid flows leftward at a rate F H and transfers heat through a pipe to a cold liquid flowing rightward at a rate Fe. 23, where the fluids are assumed to flow between well-mixed tanks with uniform temperatures. The tanks appear in pairs, and heat is conducted across the separating surfaces. The basic physical principles are that (i) the heat contained in a mass M of liquid is McuT, where Cv is the heat capacity and T is the temperature, and (ii) the rate of heat conduction across a surface is proportional to the temperature difference across it.
Write, but do not solve, the equations for the equilibrium temperatures, for given values of Fe*, FH*· Teo*. and THo*. b. Fe, /':,. Teo. and /:;THo as inputs. c. 8c, with Fe*. FH*. Teo*, and THo*. 9: a. Calculate the equilibrium values of Q*, cA *, ca*, and ce* ill terms of cAo*, T*, To*, and F*. b. Linearize about the equilibrium point. Consider Q, T0 , cAo. , as inputs. c. 6 X w- 3 m3I min. 10: a. Linearize about a set of values u*, PI*, Pz*, and F*, with P 1 * ::> Pz*. Use 6F as the output, with 6u, /:;PI, and 6P2 on the inputs.
We assume also that motions are small. 30 shows the forces and gaps in a simplified manner. 29 -------- Rear view of a magnetically levitated vehicle a. Calculate the equilibrium levitation forces mass M = 4000 kg, and F; = 0. FJ. 2 , given a vehicle b. 014 m. c. Repeat (b) for the guidance magnets, assuming F~ 1 = F~ 2 and the same S* as above. 30 point. 2 m Simplified diagram showing gaps and forces. inM I. 'if .... llf•N 1-111 rt Refe renc es d. :iFcn, and flFc 2; the wind force Fw; and the guid eway elevation zc.